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Biomolecules question

2022 · 27 Jun · Shift 2 · Q13
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Biomolecules question

2022 · 27 Jun · Shift 2 · Q13

JEE MainChemistryBiomoleculesMCQ+4 / −1
Given below are two statements. Statement I : Maltose has two α\alphaα-D-glucose units linked at C1 and C4 and is a reducing sugar. Statement II : Maltose has two monosaccharides : α\alphaα-D-glucose and β\betaβ-D-glucose linked at C1 and C6 and it is a non-reducing sugar. In the light of the above statements, choose the correct answer from the options given below :
  1. A
    Both Statement I and Statement II are true.
  2. B
    Both Statement I and Statement II are false.
  3. C
    Statement I is true but Statement II is false.
  4. D
    Statement I is false but Statement II is true.
View written solutionFree

Correct answer: C

  1. Recall the structure of maltose

    Maltose is a disaccharide formed by two glucose units.

    Its glycosidic linkage is: α(1→4)\alpha(1 \to 4)α(1→4) meaning the anomeric carbon C1C_1C1​ of one α\alphaα-D-glucose is linked to the C4C_4C4​ of the second glucose unit.

  2. Check Statement I

    Statement I says:

    • Maltose has two α\alphaα-D-glucose units
    • linked at C1C_1C1​ and C4C_4C4​
    • and is a reducing sugar

    This is correct because:

    • Maltose is indeed made of two glucose units with an α(1→4)\alpha(1\to 4)α(1→4) glycosidic bond.
    • One anomeric carbon remains free in maltose, so it behaves as a reducing sugar.

    Therefore, Statement I is true.

  3. Check Statement II

    Statement II says:

    • Maltose has α\alphaα-D-glucose and β\betaβ-D-glucose
    • linked at C1C_1C1​ and C6C_6C6​
    • and it is a non-reducing sugar

    This is incorrect because:

    • Maltose is not a 1→61\to 61→6 linked disaccharide.
    • The linkage is 1→41\to 41→4, not 1→61\to 61→6.
    • Maltose is reducing, not non-reducing.

    Therefore, Statement II is false.

  4. Choose the correct option

    Since Statement I is true and Statement II is false, the correct option is: C\boxed{\text{C}}C​

  5. Comparison with stored answer

    Stored correct answer: C\boxed{\text{C}}C​

    My derived answer matches the stored answer.

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