JEE MainChemistryBiomoleculesMCQ+4 / −1
Given below are two statements. Statement I : Maltose has two -D-glucose units linked at C1 and C4 and is a reducing sugar. Statement II : Maltose has two monosaccharides : -D-glucose and -D-glucose linked at C1 and C6 and it is a non-reducing sugar. In the light of the above statements, choose the correct answer from the options given below :
- ABoth Statement I and Statement II are true.
- BBoth Statement I and Statement II are false.
- CStatement I is true but Statement II is false.
- DStatement I is false but Statement II is true.
View written solutionFree
Correct answer: C
-
Recall the structure of maltose
Maltose is a disaccharide formed by two glucose units.
Its glycosidic linkage is: meaning the anomeric carbon of one -D-glucose is linked to the of the second glucose unit.
-
Check Statement I
Statement I says:
- Maltose has two -D-glucose units
- linked at and
- and is a reducing sugar
This is correct because:
- Maltose is indeed made of two glucose units with an glycosidic bond.
- One anomeric carbon remains free in maltose, so it behaves as a reducing sugar.
Therefore, Statement I is true.
-
Check Statement II
Statement II says:
- Maltose has -D-glucose and -D-glucose
- linked at and
- and it is a non-reducing sugar
This is incorrect because:
- Maltose is not a linked disaccharide.
- The linkage is , not .
- Maltose is reducing, not non-reducing.
Therefore, Statement II is false.
-
Choose the correct option
Since Statement I is true and Statement II is false, the correct option is:
-
Comparison with stored answer
Stored correct answer:
My derived answer matches the stored answer.
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