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Aldehydes Ketones and Carboxylic Acids question

2024 · 29 Jan · Shift 2 · Q11
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Aldehydes Ketones and Carboxylic Acids question

2024 · 29 Jan · Shift 2 · Q11

JEE MainChemistryAldehydes Ketones and Carboxylic AcidsMCQ+4 / −1
Identify the reagents used for the following conversion JEE Main 2024 (Online) 29th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 48 English
  1. A
    A=LiAlH4, B=NaOH(aq),C=NH2−NH2/KOH, ethylene glycol \mathrm{A}=\mathrm{LiAlH}_4, \mathrm{~B}=\mathrm{NaOH}_{(\mathrm{aq})}, \mathrm{C}=\mathrm{NH}_2-\mathrm{NH}_2 / \mathrm{KOH} \text {, ethylene glycol }A=LiAlH4​, B=NaOH(aq)​,C=NH2​−NH2​/KOH, ethylene glycol 
  2. B
    A=DIBAL−H,B=NaOH(aq),C=NH2−NH2/KOH, ethylene glycol \mathrm{A}=\mathrm{DIBAL}-\mathrm{H}, \mathrm{B}=\mathrm{NaOH}_{(\mathrm{aq})}, \mathrm{C}=\mathrm{NH}_2-\mathrm{NH}_2 / \mathrm{KOH} \text {, ethylene glycol }A=DIBAL−H,B=NaOH(aq)​,C=NH2​−NH2​/KOH, ethylene glycol 
  3. C
    A=LiAlH4, B=NaOH(alc),C=Zn/HCl\mathrm{A}=\mathrm{LiAlH}_4, \mathrm{~B}=\mathrm{NaOH}_{(\mathrm{alc})}, \mathrm{C}=\mathrm{Zn} / \mathrm{HCl}A=LiAlH4​, B=NaOH(alc)​,C=Zn/HCl
  4. D
    A=DIBAL−H,B=NaOH(alc),C=Zn/HCl\mathrm{A}=\mathrm{DIBAL}-\mathrm{H}, \mathrm{B}=\mathrm{NaOH}_{(\mathrm{alc})}, \mathrm{C}=\mathrm{Zn} / \mathrm{HCl}A=DIBAL−H,B=NaOH(alc)​,C=Zn/HCl
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