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Laws of Motion question

2007 · Shift 2 · Q10
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  5. /2007 · Shift 2 · Q10

Laws of Motion question

2007 · Shift 2 · Q10

JEE AdvancedPhysicsLaws of MotionMCQ+3 / −1
A particle moves in the X - Y plane under the influence of a force such that its linear momentum is p→(t)=A[i^cos⁡(kt)−j^sin⁡(kt)]\overrightarrow p \left( t \right) = A\left[ {\widehat i\cos (kt) - \widehat j\sin (kt)} \right]p​(t)=A[icos(kt)−j​sin(kt)], where A and k are constants. The angle between the force and the momentum is
  1. A
    0∘0^\circ0∘
  2. B
    30∘30^\circ30∘
  3. C
    45∘45^\circ45∘
  4. D
    90∘90^\circ90∘
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