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Laws of Motion question

2019 · Shift 2 · Q40
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Laws of Motion question

2019 · Shift 2 · Q40

JEE AdvancedPhysicsLaws of MotionMultiple correct+4 / −1
A block of mass 2M is attached to a massless spring with spring-constant k.This block is connected to two other blocks of masses M and 2M using two massless pulleys and strings. The accelerations of the blocks are a1, a2 and a3 as shown in the figure. The system is released from rest with the spring in its unstretched state. The maximum extension of the spring is x0. Which of the following option(s) is/are correct? [g is the acceleration due to gravity. Neglect friction] JEE Advanced 2019 Paper 2 Offline Physics - Laws of Motion Question 14 English
  1. A
    a2−a1=a1−a3{a_2} - {a_1} = {a_1} - {a_3}a2​−a1​=a1​−a3​
  2. B
    At an extension of x04{{{x_0}} \over 4}4x0​​ of the spring, the magnitude of acceleration of the block connected to the spring is 3g10{{3g} \over {10}}103g​.
  3. C
    x0=4Mgk{x_0} = {{4Mg} \over k}x0​=k4Mg​
  4. D
    When spring achieves an extension of x02{{{x_0}} \over 2}2x0​​ for the first time, the speed of the block connected to the spring is 3gM5k3g\sqrt {{M \over {5k}}}3g5kM​​
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