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Laws of Motion question

2007 · Shift 1 · Q47
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Laws of Motion question

2007 · Shift 1 · Q47

JEE AdvancedPhysicsLaws of MotionMCQ+3 / −1
Two particles of mass m each are tied at the ends of a light string of length 2a. The whole system is kept on a frictionless horizontal surface with the string held tight so that each mass is at a distance 'a' form the centre P (as shown in the figure). Now, the mid-point of the string is pulled vertically upwards with a small but constant force F. As a result, the particles move towards each other on the surface. The magnitude of acceleration, with the separation between them becomes 2x, is IIT-JEE 2007 Paper 1 Offline Physics - Laws of Motion Question 7 English
  1. A
    F2maa2−x2{F \over {2m}}{a \over {\sqrt {{a^2} - {x^2}} }}2mF​a2−x2​a​
  2. B
    F2mxa2−x2{F \over {2m}}{x \over {\sqrt {{a^2} - {x^2}} }}2mF​a2−x2​x​
  3. C
    F2mxa{F \over {2m}}{x \over a}2mF​ax​
  4. D
    F2ma2−x2x{F \over {2m}}{{\sqrt {{a^2} - {x^2}} } \over x}2mF​xa2−x2​​
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