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Probability question

2015 · Shift 2 · Q25
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  5. /2015 · Shift 2 · Q25

Probability question

2015 · Shift 2 · Q25

JEE AdvancedMathematicsProbabilityMultiple correct+4 / −1
Let n1{n_1}n1​ and n2{n_2}n2​ be the number of red and black balls, respectively, in box I{\rm I}I. Let n3{n_3}n3​ and n4{n_4}n4​ be the number of red and black balls, respectively, in box II.{\rm I}{\rm I}.II. A ball is drawn at random from box I{\rm I}I and transferred to box II.{\rm I}{\rm I}.II. If the probability of drawing a red ball from box I,{\rm I},I, after this transfer, is 13,{1 \over 3},31​, then the correct option(s) with the possible values of n1{n_1}n1​ and n2{n_2}n2​ is(are)
  1. A
    n1=4{n_1} = 4n1​=4 and n2=6{n_2} = 6n2​=6
  2. B
    n1=2{n_1} = 2n1​=2 and n2=3{n_2} = 3n2​=3
  3. C
    n1=10{n_1} = 10n1​=10 and n2=20{n_2} = 20n2​=20
  4. D
    n1=3{n_1} = 3n1​=3 and n2=6{n_2} = 6n2​=6
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