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Probability question

2015 · Shift 2 · Q24

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PYQ Library
JEE Advanced
Mathematics
Probability
2015 · Shift 2 · Q24

Probability question

2015 · Shift 2 · Q24

JEE AdvancedMathematicsProbabilityMultiple correct+4 / −1

Let

{n_1}

and

{n_2}

be the number of red and black balls, respectively, in box

{\rm I}

. Let

{n_3}

and

{n_4}

be the number of red and black balls, respectively, in box

{\rm I}{\rm I}.

One of the two boxes, box

{\rm I}

and box

{\rm I}{\rm I},

was selected at random and a ball was drawn randomly out of this box. The ball was found to be red. If the probability that this red ball was drawn from box

{\rm I}{\rm I}

is

{1 \over 3},

then the correct option(s) with the possible values of

{n_1}{n_2},{n_3}

and

{n_4}

is (are)

A
${n_1} = 3,{n_2} = 3,{n_3} = 5,{n_4} = 15$
B
${n_1} = 3,{n_2} = 6,{n_3} = 10,{n_4} = 50$
C
${n_1} = 8,{n_2} = 6,{n_3} = 5,{n_4} = 20$
D
${n_1} = 6,{n_2} = 12,{n_3} = 5,{n_4} = 20$

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