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Hyperbola question

2015 · Shift 2 · Q30
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  5. /2015 · Shift 2 · Q30

Hyperbola question

2015 · Shift 2 · Q30

JEE AdvancedMathematicsHyperbolaMultiple correct+4 / −1
Consider the hyperbola H:x2−y2=1H:{x^2} - {y^2} = 1H:x2−y2=1 and a circle SSS with center N(x2,0)N\left( {{x_2},0} \right)N(x2​,0). Suppose that HHH and SSS touch each other at a point P(x1,y1)P\left( {{x_1},{y_1}} \right)P(x1​,y1​) with x1>1{{x_1} \gt 1}x1​>1 and y1>0{{y_1} \gt 0}y1​>0. The common tangent to HHH and SSS at PPP intersects the xxx-axis at point MMM. If (l,m)(l, m)(l,m) is the centroid of the triangle PMNPMNPMN, then the correct expressions(s) is(are)
  1. A
    dldx1=1−13x12{{dl} \over {d{x_1}}} = 1 - {1 \over {3x_1^2}}dx1​dl​=1−3x12​1​ for x1>1{x_1} \gt 1x1​>1
  2. B
    dmdx1=x13(x12−1){{dm} \over {d{x_1}}} = {{{x_1}} \over {3\left( {\sqrt {x_1^2 - 1} } \right)}}dx1​dm​=3(x12​−1​)x1​​ for x1>1{x_1} \gt 1x1​>1
  3. C
    dldx1=1+13x12{{dl} \over {d{x_1}}} = 1 + {1 \over {3x_1^2}}dx1​dl​=1+3x12​1​ for x1>1{x_1} \gt 1x1​>1
  4. D
    dmdy1=13{{dm} \over {d{y_1}}} = {1 \over 3}dy1​dm​=31​ for y1>0{y_1} \gt 0y1​>0
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