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Hyperbola question

2007 · Shift 1 · Q28
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  5. /2007 · Shift 1 · Q28

Hyperbola question

2007 · Shift 1 · Q28

JEE AdvancedMathematicsHyperbolaMCQ+3 / −1
A hyperbola, having the transverse axis of the length 2sin⁡θ2\sin \theta2sinθ, is confocal with the ellipse 3x2+4y2=123{x^2} + 4{y^2} = 123x2+4y2=12. Then its equation is
  1. A
    x2cos⁡ec2θ−y2sec⁡2θ=1{x^2}\cos e{c^2}\theta - {y^2}{\sec ^2}\theta = 1x2cosec2θ−y2sec2θ=1
  2. B
    x2sec⁡2θ−y2cos⁡ec2θ=1{x^2}{\sec ^2}\theta - {y^2}\cos e{c^2}\theta = 1x2sec2θ−y2cosec2θ=1
  3. C
    x2sin⁡2θ−y2cos⁡2θ=1{x^2}{\sin ^2}\theta - {y^2}{\cos ^2}\theta = 1x2sin2θ−y2cos2θ=1
  4. D
    x2cos⁡2θ−y2sin⁡2θ=1{x^2}{\cos ^2}\theta - {y^2}{\sin ^2}\theta = 1x2cos2θ−y2sin2θ=1
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