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Hyperbola question

2011 · Shift 1 · Q31
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  2. /JEE Advanced
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  5. /2011 · Shift 1 · Q31

Hyperbola question

2011 · Shift 1 · Q31

JEE AdvancedMathematicsHyperbolaMultiple correct+4 / −1
Let the eccentricity of the hyperbola x2a2−y2b2=1{{{x^2}} \over {{a^2}}} - {{{y^2}} \over {{b^2}}} = 1a2x2​−b2y2​=1 be reciprocal to that of the ellipse x2+4y2=4{x^2} + 4{y^2} = 4x2+4y2=4. If the hyperbola passes through a focus of the ellipse, then
  1. A
    the equation of the hyperbola is x23−y22=1{{{x^2}} \over 3} - {{{y^2}} \over 2} = 13x2​−2y2​=1
  2. B
    a focus of the hyperbola is (2,0)(2, 0)(2,0)
  3. C
    theeccentricity of the hyperbola is 53\sqrt {{5 \over 3}}35​​
  4. D
    The equation of the hyperbola is x2−3y2=3{x^2} - 3{y^2} = 3x2−3y2=3
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