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Hyperbola question

2010 · Shift 1 · Q36

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PYQ Library
JEE Advanced
Mathematics
Hyperbola
2010 · Shift 1 · Q36

Hyperbola question

2010 · Shift 1 · Q36

JEE AdvancedMathematicsHyperbolaMCQ+4 / −1

The circle

{x^2} + {y^2} - 8x = 0

and hyperbola

{{{x^2}} \over 9} - {{{y^2}} \over 4} = 1

intersect at the points

A

and

B

. Equation of a common tangent with positive slope to the circle as well as to the hyperbola is

A
$2x - \sqrt {5y} - 20 = 0$
B
$2x - \sqrt {5y} + 4 = 0$
C
$3x - 4y + 8 = 0$
D
$4x - 3y + 4 = 0$

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