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Hyperbola question

2010 · Shift 1 · Q38
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  5. /2010 · Shift 1 · Q38

Hyperbola question

2010 · Shift 1 · Q38

JEE AdvancedMathematicsHyperbolaNumerical+4 / −1
The line 2x+y=12x + y = 12x+y=1 is tangent to the hyperbola x2a2−y2b2=1{{{x^2}} \over {{a^2}}} - {{{y^2}} \over {{b^2}}} = 1a2x2​−b2y2​=1. If this line passes through the point of intersection of the nearest directrix and the xxx-axis, then the eccentricity of the hyperbola is
Numerical answer
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