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Hyperbola question

2010 · Shift 1 · Q37
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  2. /JEE Advanced
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  5. /2010 · Shift 1 · Q37

Hyperbola question

2010 · Shift 1 · Q37

JEE AdvancedMathematicsHyperbolaMCQ+4 / −1
The circle x2+y2−8x=0{x^2} + {y^2} - 8x = 0x2+y2−8x=0 and hyperbola x29−y24=1{{{x^2}} \over 9} - {{{y^2}} \over 4} = 19x2​−4y2​=1 intersect at the points AAA and BBB. Equation of the circle with ABABAB as its diameter is
  1. A
    x2+y2−12x+24=0{x^2} + {y^2} - 12x + 24 = 0x2+y2−12x+24=0
  2. B
    x2+y2+12x+24=0{x^2} + {y^2} + 12x + 24 = 0x2+y2+12x+24=0
  3. C
    x2+y2+24x−12=0{x^2} + {y^2} + 24x - 12 = 0x2+y2+24x−12=0
  4. D
    x2+y2−24x−12=0{x^2} + {y^2} - 24x - 12 = 0x2+y2−24x−12=0
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