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Application of Integration question

2009 · Shift 1 · Q29
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  5. /2009 · Shift 1 · Q29

Application of Integration question

2009 · Shift 1 · Q29

JEE AdvancedMathematicsApplication of IntegrationMCQ+3 / −1
Let fff be a non-negative function defined on the interval [0,1][0,1][0,1]. If ∫0x1−(f′(t))2dt=∫0xf(t)dt,0≤x≤1\int\limits_0^x {\sqrt {1 - {{(f'(t))}^2}dt} = \int\limits_0^x {f(t)dt,0 \le x \le 1} }0∫x​1−(f′(t))2dt​=0∫x​f(t)dt,0≤x≤1, and f(0)=0f(0) = 0f(0)=0, then
  1. A
    f(12)<12f\left( {{1 \over 2}} \right) \lt {1 \over 2}f(21​)<21​ and f(13)>13f\left( {{1 \over 3}} \right) \gt {1 \over 3}f(31​)>31​
  2. B
    f(12)>12f\left( {{1 \over 2}} \right) \gt {1 \over 2}f(21​)>21​ and f(13)>13f\left( {{1 \over 3}} \right) \gt {1 \over 3}f(31​)>31​
  3. C
    f(12)<12f\left( {{1 \over 2}} \right) \lt {1 \over 2}f(21​)<21​ and f(13)<13f\left( {{1 \over 3}} \right) \lt {1 \over 3}f(31​)<31​
  4. D
    f(12)>12f\left( {{1 \over 2}} \right) \gt {1 \over 2}f(21​)>21​ and f(13)<13f\left( {{1 \over 3}} \right) \lt {1 \over 3}f(31​)<31​
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