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Application of Integration question

2023 · Shift 1 · Q26
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  5. /2023 · Shift 1 · Q26

Application of Integration question

2023 · Shift 1 · Q26

JEE AdvancedMathematicsApplication of IntegrationNumerical+4 / −1
Let n≥2n \geq 2n≥2 be a natural number and f:[0,1]→Rf:[0,1] \rightarrow \mathbb{R}f:[0,1]→R be the function defined by f(x)={n(1−2nx) if 0≤x≤12n2n(2nx−1) if 12n≤x≤34n4n(1−nx) if 34n≤x≤1nnn−1(nx−1) if 1n≤x≤1f(x)= \begin{cases}n(1-2 n x) & \text { if } 0 \leq x \leq \frac{1}{2 n} \\\\ 2 n(2 n x-1) & \text { if } \frac{1}{2 n} \leq x \leq \frac{3}{4 n} \\\\ 4 n(1-n x) & \text { if } \frac{3}{4 n} \leq x \leq \frac{1}{n} \\\\ \frac{n}{n-1}(n x-1) & \text { if } \frac{1}{n} \leq x \leq 1\end{cases}f(x)=⎩⎨⎧​n(1−2nx)2n(2nx−1)4n(1−nx)n−1n​(nx−1)​ if 0≤x≤2n1​ if 2n1​≤x≤4n3​ if 4n3​≤x≤n1​ if n1​≤x≤1​ If nnn is such that the area of the region bounded by the curves x=0,x=1,y=0x=0, x=1, y=0x=0,x=1,y=0 and y=f(x)y=f(x)y=f(x) is 4 , then the maximum value of the function fff is :
Numerical answer
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