New chat PYQ Library Doubts Rank report

Sign in to see Recents

Sign in to save progress →

Application of Derivatives question

2012 · Shift 1 · Q31

Guest · try one question or challengeGuest · try one question or challenge

PYQ Library
JEE Advanced
Mathematics
Application of Derivatives
2012 · Shift 1 · Q31

Application of Derivatives question

2012 · Shift 1 · Q31

JEE AdvancedMathematicsApplication of DerivativesNumerical+4 / −1

Let

p(x)

be a real polynomial of least degree which has a local maximum at

x=1

and a local minimum at

x=3

. If

p(1)=6

and

p(3)=2

, then

p'(0)

is

Numerical answer

More from Application of Derivatives

Let $f (x) = (1 - x)^{2} sin^{2} x + x^{2}$ for all $x \in I R$ and let $g (x) = 1 \int x (\frac{2 ( t - 1 )}{t + 1} - I n t) f (t) d t$ for…2012 · MCQ
Let $f (x) = (1 - x)^{2} sin^{2} x + x^{2}$ for all $x \in I R$ and let $g (x) = 1 \int x (\frac{2 ( t - 1 )}{t + 1} - I n t) f (t) d t$ for…2012 · MCQ
If $f (x) = \int_{0}^{x} e^{t^{2}} (t - 2) (t - 3) d t$ for all $x \in (0, \infty),$ then2012 · Multiple correct
Let $f$ be a real-valued differentiable function on $R$ (the set of all real numbers) such that $f (1) = 1$ . If the $y$ -intercept of the tangent at any point $P (x, y)$ on the curve $y = f (x)$ is equal to the cube of the abscissa of $P$ , then find…2010 · Numerical
Let $f$ be a function defined on $R$ (the set of all real numbers) such that $f^{'} (x) = 2010 (x - 2009) (x - 2010)^{2} (x - 2011)^{3} (x - 2012)^{4}$ for all $x \in R$ If $g$ …2010 · Numerical
The maximum value of the function $f (x) = 2 x^{3} - 15 x^{2} + 36 x - 48$ on the set $A = {x ∣ x^{2} + 20 \leq 9 x ∣}$ is .2009 · Numerical
Let $p (x)$ be a polynomial of degree $4$ having extremum at $x = 1, 2$ and $x \to 0 lim (1 + \frac{p ( x )}{x ^{2}}) = 2$ . Then the value of $p (2)$ is2009 · Numerical
For the function $f (x) = x cos \frac{1}{x}, x \geq 1,$ 2009 · Multiple correct