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Application of Derivatives question

2009 · Shift 2 · Q26
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  5. /2009 · Shift 2 · Q26

Application of Derivatives question

2009 · Shift 2 · Q26

JEE AdvancedMathematicsApplication of DerivativesNumerical+4 / −1
The maximum value of the function f(x)=2x3−15x2+36x−48f(x) = 2{x^3} - 15{x^2} + 36x - 48f(x)=2x3−15x2+36x−48 on the set A={x∣x2+20≤9x∣}A = \{ x|{x^2} + 20 \le 9x|\}A={x∣x2+20≤9x∣} is ‾\underline{\hspace{2cm}}​.
Numerical answer
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