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Application of Derivatives question

2009 · Shift 2 · Q27
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  5. /2009 · Shift 2 · Q27

Application of Derivatives question

2009 · Shift 2 · Q27

JEE AdvancedMathematicsApplication of DerivativesNumerical+3 / −1
Let p(x)p(x)p(x) be a polynomial of degree 444 having extremum at x=1,2x = 1,2x=1,2 and lim⁡x→0(1+p(x)x2)=2\mathop {\lim }\limits_{x \to 0} \left( {1 + {{p\left( x \right)} \over {{x^2}}}} \right) = 2x→0lim​(1+x2p(x)​)=2. Then the value of p(2)p (2)p(2) is
Numerical answer
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