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Thermodynamics question

2009 · Shift 2 · Q12
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Thermodynamics question

2009 · Shift 2 · Q12

JEE AdvancedChemistryThermodynamicsNumerical+3 / −1
In a constant volume calorimeter, 3.5 g of a gas with molecular weight 28 was burnt in excess oxygen at 298.0 K. The temperature of the calorimeter was found to increase from 298.0 K to 298.45 K due to the combustion process. Given that the heat capacity of the calorimeter is 2.5 kJ K −1{}^{-1}−1, the numerical value for the enthalpy of combustion of the gas in kJ mol −1{}^{-1}−1 is ‾\underline{\hspace{2cm}}​.
Numerical answer
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