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Solid State question

2020 · Shift 1 · Q12
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Solid State question

2020 · Shift 1 · Q12

JEE AdvancedChemistrySolid StateMultiple correct+4 / −2
The cubic unit cell structure of a compound containing cation M and anion X is shown below. When compared to the anion, the cation has smaller ionic radius. Choose the correct statement(s). JEE Advanced 2020 Paper 1 Offline Chemistry - Solid State Question 14 English
  1. A
    The empirical formula of the compound is MX.
  2. B
    The cation M and anion X have different coordination geometries.
  3. C
    The ratio of M −-− X bond length of the cubic unit cell edge length is 0.866.
  4. D
    The ratio of the ionic radii of cation M to anion X is 0.414.
View written solutionFree

Correct answer: A, C

  1. Identify the structure from the cubic unit cell

    The figure described is the standard rock-salt (NaCl type) arrangement: one ion forms an FCC lattice and the other occupies all octahedral voids.

    Since the cation MMM is smaller than the anion XXX, the larger anion XXX forms the FCC framework and the smaller cation MMM occupies octahedral holes.


  1. Find the empirical formula

    In an FCC lattice of anions XXX:

    • Corner anions: 8×18=18 \times \frac{1}{8} = 18×81​=1
    • Face-center anions: 6×12=36 \times \frac{1}{2} = 36×21​=3

    So total anions per unit cell: 1+3=41+3=41+3=4

    Octahedral holes in FCC = 4 per unit cell, all occupied by MMM.

    So total cations per unit cell = 4.

    Hence, M:X=4:4=1:1M:X = 4:4 = 1:1M:X=4:4=1:1

    Therefore, the empirical formula is: MX\boxed{MX}MX​

    So A is correct.


  1. Check coordination geometries

    In NaCl-type structure:

    • Each cation MMM is surrounded by 6 anions XXX.
    • Each anion XXX is surrounded by 6 cations MMM.

    Thus, both have octahedral coordination.

    Therefore, cation and anion do not have different coordination geometries.

    So B is incorrect.


  1. Find the ratio of M−XM-XM−X bond length to cube edge length

    In rock-salt structure, nearest M−XM-XM−X contact occurs along the edge of the cube.

    If cube edge length is aaa, then the distance between nearest cation and anion is: a2\frac{a}{2}2a​

    Therefore, M-X bond lengthedge length=a/2a=12=0.5\frac{\text{M-X bond length}}{\text{edge length}} = \frac{a/2}{a} = \frac{1}{2} = 0.5edge lengthM-X bond length​=aa/2​=21​=0.5

    So option C, which says 0.8660.8660.866, is incorrect for NaCl structure.


  1. Check radius ratio

    For octahedral coordination (coordination number 6), the limiting radius ratio is: r+r−=0.414\frac{r_+}{r_-} = 0.414r−​r+​​=0.414

    But this is only the minimum radius ratio required for stable octahedral coordination, not an exact value that must hold for every compound.

    The statement says the ratio is 0.4140.4140.414, which is not necessarily true.

    So D is incorrect.


  1. Final derived answer

    Correct option(s): A\boxed{A}A​


  1. Comparison with stored correct answer

    Stored answer: A,CA, CA,C

    My derived answer is only AAA.

    I disagree with the stored answer because in the NaCl-type cubic unit cell, the nearest M−XM-XM−X distance is a/2a/2a/2, not 0.866a0.866a0.866a.

    The value 0.866=3/20.866 = \sqrt{3}/20.866=3​/2 is associated with half the body diagonal, which does not represent nearest cation-anion contact in this structure.

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