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Solid State question

2010 · Shift 2 · Q10
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Solid State question

2010 · Shift 2 · Q10

JEE AdvancedChemistrySolid StateMCQ+3 / −1
The packing efficiency of the twodimensional square unit cell shown below is IIT-JEE 2010 Paper 2 Offline Chemistry - Solid State Question 2 English
  1. A
    39.27%39.27 \%39.27%
  2. B
    68.02%68.02 \%68.02%
  3. C
    74.05%74.05 \%74.05%
  4. D
    78.54%78.54 \%78.54%
View written solutionFree

Correct answer: D

  1. Interpret the 2D square unit cell

    In a two-dimensional square packing, particles (circles) are located at the four corners of a square.

    If the radius of each circle is rrr, then for square packing the circles touch along the side of the square.

    Hence, side of the square unit cell is a=2ra = 2ra=2r

  2. Find the effective number of circles in one unit cell

    Each corner circle contributes only one-fourth to the unit cell.

    Since there are 4 corner circles, 4×14=14 \times \frac{1}{4} = 14×41​=1

    So, the unit cell contains effectively 1 circle.

  3. Area occupied by circles inside the unit cell

    Area of one circle is πr2\pi r^2πr2

    Since effectively there is 1 circle in the unit cell, total occupied area is Aoccupied=πr2A_{\text{occupied}} = \pi r^2Aoccupied​=πr2

  4. Total area of the square unit cell

    Acell=a2=(2r)2=4r2A_{\text{cell}} = a^2 = (2r)^2 = 4r^2Acell​=a2=(2r)2=4r2

  5. Packing efficiency

    Packing efficiency=AoccupiedAcell×100\text{Packing efficiency} = \frac{A_{\text{occupied}}}{A_{\text{cell}}} \times 100Packing efficiency=Acell​Aoccupied​​×100

    =πr24r2×100= \frac{\pi r^2}{4r^2} \times 100=4r2πr2​×100

    =π4×100= \frac{\pi}{4} \times 100=4π​×100

    Using π≈3.1416\pi \approx 3.1416π≈3.1416, Packing efficiency=3.14164×100≈78.54%\text{Packing efficiency} = \frac{3.1416}{4} \times 100 \approx 78.54\%Packing efficiency=43.1416​×100≈78.54%

  6. Match with options

    78.54%78.54\%78.54% corresponds to Option D.


Comparison with stored correct answer:

Stored correct answer = D

Derived answer = D

So, they agree.

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