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Solid State question

2011 · Shift 2 · Q5
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  5. /2011 · Shift 2 · Q5

Solid State question

2011 · Shift 2 · Q5

JEE AdvancedChemistrySolid StateNumerical+1 / −1
The number of hexagonal faces that are present in a truncated octahedron is ‾\underline{\hspace{2cm}}​.
Numerical answer
View written solutionFree

Correct answer: 8

  1. A truncated octahedron is obtained by cutting off the vertices of an octahedron.

  2. It is a well-known Archimedean solid with:

    • 888 regular hexagonal faces
    • 666 square faces

  3. Therefore, the number of hexagonal faces in a truncated octahedron is:

888

  1. Comparing with the stored correct answer:
    • Stored answer = 888
    • Derived answer = 888

So, the derived answer agrees with the stored correct answer.

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