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Redox Reactions question

2015 · Shift 1 · Q19
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Redox Reactions question

2015 · Shift 1 · Q19

JEE AdvancedChemistryRedox ReactionsMultiple correct+4 / −2
Fe3+Fe^{3+}Fe3+ is reduced to Fe2+Fe^{2+}Fe2+ by using
  1. A
    H2O2H_2O_2H2​O2​ in presence of NaOHNaOHNaOH.
  2. B
    Na2O2Na_2O_2Na2​O2​ in water.
  3. C
    H2O2H_2O_2H2​O2​ in presence of H2SO4H_2SO_4H2​SO4​.
  4. D
    Na2O2Na_2O_2Na2​O2​ in presence of H2SO4H_2SO_4H2​SO4​.
View written solutionFree

Correct answer: C, D

  1. Identify what is needed

We need a reagent that will reduce Fe3+Fe^{3+}Fe3+ to Fe2+Fe^{2+}Fe2+.

That means the reagent itself must act as a reducing agent.

Fe3++e−→Fe2+Fe^{3+} + e^- \rightarrow Fe^{2+}Fe3++e−→Fe2+

So we must check in which medium the given peroxide species behave as reducing agents.


  1. Key redox behavior of peroxides

(i) H2O2H_2O_2H2​O2​

Hydrogen peroxide can act as both:

  • oxidizing agent
  • reducing agent

Its behavior depends on the medium and the reacting species.

A very important reaction is:

2Fe3++H2O2→2Fe2++O2+2H+2Fe^{3+} + H_2O_2 \rightarrow 2Fe^{2+} + O_2 + 2H^+2Fe3++H2​O2​→2Fe2++O2​+2H+

Here, H2O2H_2O_2H2​O2​ is oxidized to O2O_2O2​, so it acts as a reducing agent. Thus it can reduce Fe3+Fe^{3+}Fe3+ to Fe2+Fe^{2+}Fe2+.

This is feasible in acidic medium.


(ii) In alkaline medium

In presence of NaOHNaOHNaOH, H2O2H_2O_2H2​O2​ generally shows strong oxidizing behavior because of formation of peroxide/hydroperoxide species in base. It is not the standard reagent used for reducing Fe3+Fe^{3+}Fe3+ to Fe2+Fe^{2+}Fe2+.

So option A is not correct.


  1. Check each option

Option A: H2O2H_2O_2H2​O2​ in presence of NaOHNaOHNaOH

In alkaline medium, H2O2H_2O_2H2​O2​ is not used here as a reducing agent for Fe3+Fe^{3+}Fe3+.

So, A is incorrect.


Option B: Na2O2Na_2O_2Na2​O2​ in water

Na2O2Na_2O_2Na2​O2​ in water gives hydrogen peroxide:

Na2O2+2H2O→2NaOH+H2O2Na_2O_2 + 2H_2O \rightarrow 2NaOH + H_2O_2Na2​O2​+2H2​O→2NaOH+H2​O2​

This produces alkaline medium along with H2O2H_2O_2H2​O2​. Since the medium becomes basic, this does not favor reduction of Fe3+Fe^{3+}Fe3+ to Fe2+Fe^{2+}Fe2+.

So, B is incorrect.


Option C: H2O2H_2O_2H2​O2​ in presence of H2SO4H_2SO_4H2​SO4​

This is acidic medium. In acidic medium, H2O2H_2O_2H2​O2​ can reduce Fe3+Fe^{3+}Fe3+ to Fe2+Fe^{2+}Fe2+:

2Fe3++H2O2→2Fe2++O2+2H+2Fe^{3+} + H_2O_2 \rightarrow 2Fe^{2+} + O_2 + 2H^+2Fe3++H2​O2​→2Fe2++O2​+2H+

So, C is correct.


Option D: Na2O2Na_2O_2Na2​O2​ in presence of H2SO4H_2SO_4H2​SO4​

First, Na2O2Na_2O_2Na2​O2​ with acid generates H2O2H_2O_2H2​O2​:

Na2O2+H2SO4→Na2SO4+H2O2Na_2O_2 + H_2SO_4 \rightarrow Na_2SO_4 + H_2O_2Na2​O2​+H2​SO4​→Na2​SO4​+H2​O2​

Since the medium is acidic, the generated H2O2H_2O_2H2​O2​ can reduce Fe3+Fe^{3+}Fe3+ to Fe2+Fe^{2+}Fe2+.

So, D is correct.


  1. Final conclusion

The reagents that reduce Fe3+Fe^{3+}Fe3+ to Fe2+Fe^{2+}Fe2+ are:

C,D\boxed{C, D}C,D​


  1. Comparison with stored correct answer

Stored correct answer: A, B

Derived answer: C, D

These do not match. The stored answer appears incorrect because reduction of Fe3+Fe^{3+}Fe3+ by peroxide is favored in acidic medium, not in alkaline medium.

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