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Polymers question

2025 · Shift 1 · Q12
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Polymers question

2025 · Shift 1 · Q12

JEE AdvancedChemistryPolymersNumerical+4 / −1
The monomer (X) involved in the synthesis of Nylon 6,6 gives positive carbylamine test. If 10 moles of X are analyzed using Dumas method, the amount (in grams) of nitrogen gas evolved is ‾\underline{\hspace{2cm}}​. Use: Atomic mass of N (in amu) = 14
Numerical answer
View written solutionFree

Correct answer: 280

Step-by-step Derivation:

  1. Identify the Monomers of Nylon 6,6: Nylon 6,6 is a condensation polymer formed from two monomers, each containing 6 carbon atoms. These monomers are:

    • Hexamethylenediamine: H₂N-(CH₂)₆-NH₂
    • Adipic acid: HOOC-(CH₂)₄-COOH
  2. Identify the Monomer (X): The problem states that monomer (X) gives a positive carbylamine test. The carbylamine test (also known as Hoffmann's isocyanide test) is a specific test for primary amines (-NH₂ group).

    • Hexamethylenediamine has two primary amine groups, so it will give a positive carbylamine test.
    • Adipic acid is a carboxylic acid and does not have an amine group, so it will give a negative test. Therefore, the monomer (X) is hexamethylenediamine.
  3. Determine the Chemical Formula of Monomer (X): The chemical formula for hexamethylenediamine, H₂N-(CH₂)₆-NH₂, is C₆H₁₆N₂. From the formula, we can see that one molecule of hexamethylenediamine contains two nitrogen atoms.

  4. Relate Monomer (X) to Nitrogen Gas in the Dumas Method: The Dumas method is used for the quantitative estimation of nitrogen. In this method, all the nitrogen present in the organic compound is converted into nitrogen gas (N₂). The monomer (X) has the formula C₆H₁₆N₂. It contains 2 nitrogen atoms per molecule. These 2 nitrogen atoms combine to form one molecule of nitrogen gas (N₂). So, the stoichiometric relationship is: 1 molecule of C6H16N2⟶1 molecule of N21 \text{ molecule of } C₆H₁₆N₂ \longrightarrow 1 \text{ molecule of } N₂1 molecule of C6​H16​N2​⟶1 molecule of N2​ On a molar basis: 1 mole of C6H16N2⟶1 mole of N21 \text{ mole of } C₆H₁₆N₂ \longrightarrow 1 \text{ mole of } N₂1 mole of C6​H16​N2​⟶1 mole of N2​

  5. Calculate the Moles of Nitrogen Gas Evolved: We are given that 10 moles of monomer (X) are analyzed. Based on the stoichiometry from Step 4, 10 moles of X will produce 10 moles of N₂ gas. Moles of N₂ evolved = 10 mol.

  6. Calculate the Mass of Nitrogen Gas Evolved: The mass of a substance is calculated by multiplying its moles by its molar mass.

    • Atomic mass of Nitrogen (N) = 14 amu. So, the molar mass of N is 14 g/mol.
    • Molar mass of nitrogen gas (N₂) = 2 × 14 g/mol = 28 g/mol.

    Mass of N₂ evolved = Moles of N₂ × Molar mass of N₂ Mass of N₂ evolved = 10 mol×28 g/mol10 \text{ mol} × 28 \text{ g/mol}10 mol×28 g/mol Mass of N₂ evolved = 280 g.

Final Answer:

The amount of nitrogen gas evolved is 280 grams.

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