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Polymers question

2009 · Shift 1 · Q8
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  5. /2009 · Shift 1 · Q8

Polymers question

2009 · Shift 1 · Q8

JEE AdvancedChemistryPolymersMCQ+3 / −1
Among cellulose, poly(vinyl chloride), nylon and natural rubber, the polymer in which the intermolecular force of attraction is weakest is
  1. A
    Nylon
  2. B
    Poly(vinyl chloride)
  3. C
    Cellulose
  4. D
    Natural Rubber
View written solutionFree

Correct answer: D

  1. Identify the type of intermolecular forces in each polymer

    The strength of intermolecular attraction in polymers depends on polarity, hydrogen bonding, and structure.

  2. Analyze each option

    A. Nylon

    • Nylon contains amide linkages, −CONH−-CONH-−CONH−.
    • These groups are highly polar and can form strong hydrogen bonds between polymer chains.
    • Hence, nylon has strong intermolecular forces.

    B. Poly(vinyl chloride) (PVC)

    • PVC contains polar C−ClC-ClC−Cl bonds.
    • Due to polarity, there are dipole-dipole attractions between chains.
    • These are weaker than hydrogen bonding but still significant.

    C. Cellulose

    • Cellulose has a large number of −OH-OH−OH groups.
    • These groups form extensive intermolecular hydrogen bonding.
    • So, cellulose has very strong intermolecular forces.

    D. Natural rubber

    • Natural rubber is cis-1,4-polyisoprene.
    • It is essentially a non-polar hydrocarbon polymer.
    • Therefore, the intermolecular forces are mainly weak van der Waals forces.
    • Hence, it has the weakest intermolecular attraction among the given polymers.

  3. Conclusion

    The polymer with the weakest intermolecular force of attraction is: Natural Rubber\boxed{\text{Natural Rubber}}Natural Rubber​

  4. Option check

    • A: Nylon  strong H-bonding
    • B: PVC  dipole-dipole attraction
    • C: Cellulose  extensive H-bonding
    • D: Natural Rubber  weakest, only van der Waals forces

Therefore, the correct option is D.

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