This problem requires matching chemical substances with their classification (natural/synthetic polymer) and the type of chemical bonds they contain. Let's analyze each substance in Column I.

Step 1: Analyze Cellulose (A)

1. Classification: Cellulose is a polysaccharide that is the primary structural component of the cell walls of green plants. Since it is obtained from nature, it is a (P) natural polymer.
2. Bond Type: Cellulose is a polymer made of repeating monomer units of β-D-glucose. These glucose units are linked together by β-1,4-glycosidic bonds. Therefore, cellulose contains (S) glycoside linkage.
3. Conclusion: Cellulose matches with both (P) and (S).
   • A → (p, s)

Step 2: Analyze Nylon-6, 6 (B)

1. Classification: Nylon-6, 6 is a polyamide produced by the condensation polymerization of hexamethylenediamine and adipic acid. It is a man-made, artificial polymer, hence it is a (Q) synthetic polymer.
2. Bond Type: The reaction between the amine group (-NH₂) of hexamethylenediamine and the carboxylic acid group (-COOH) of adipic acid forms an amide bond (–CO–NH–). This linkage is repeated throughout the polymer chain. $n \, \text{HOOC(CH}_2)_4\text{COOH} + n \, \text{H}_2\text{N(CH}_2)_6\text{NH}_2 \longrightarrow [–\text{OC(CH}_2)_4\text{CO}–\text{NH(CH}_2)_6\text{NH}–]_n + 2n \, \text{H}_2\text{O}$ Therefore, Nylon-6, 6 contains (R) amide linkage.
3. Conclusion: Nylon-6, 6 matches with both (Q) and (R).
   • B → (q, r)

Step 3: Analyze Protein (C)

1. Classification: Proteins are large biomolecules, or macromolecules, consisting of one or more long chains of amino acid residues. They are found in all living organisms and are produced naturally. Thus, a protein is a (P) natural polymer.
2. Bond Type: The amino acids in a protein are joined together by peptide bonds. A peptide bond is a covalent chemical bond formed between two molecules when the carboxyl group of one molecule reacts with the amino group of the other molecule, releasing a molecule of water (H₂O). This is a dehydration synthesis reaction (also known as a condensation reaction), and it usually occurs between amino acids. The resulting C(O)NH bond is called a peptide bond, which is a specific type of (R) amide linkage.
3. Conclusion: Protein matches with both (P) and (R).
   • C → (p, r)

Step 4: Analyze Sucrose (D)

1. Classification: Sucrose (common table sugar) is a disaccharide, which is a molecule composed of two monosaccharides: glucose and fructose. A disaccharide is not a polymer, as polymers consist of a large number of repeating monomer units. So, sucrose does not match with (P) or (Q).
2. Bond Type: In sucrose, the glucose and fructose units are joined by a glycosidic bond between carbon atom 1 of the glucose unit and carbon atom 2 of the fructose unit. Therefore, sucrose contains a (S) glycoside linkage.
3. Conclusion: Sucrose matches with (S).
   • D → (s)

Step 5: Match with Options

Based on the analysis:

• A → (p, s)
• B → (q, r)
• C → (p, r)
• D → (s)

Let's check the given options:

• A: A - (p, s); B - (q); C - (p, r); D - (s) --- Incorrect, B is also (r).
• B: A - (p, s); B - (q, r); C - (r); D - (s) --- Incorrect, C is also (p).
• C: A - (p, s); B - (q, r); C - (p, r); D - (s) --- Correct.
• D: A - (s); B - (q, r); C - (p, r); D - (s) --- Incorrect, A is also (p).

The correct option is C.