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Polymers question

2015 · Shift 2 · Q17
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Polymers question

2015 · Shift 2 · Q17

JEE AdvancedChemistryPolymersMultiple correct+4 / −2
Under hydrolytic conditions, the compounds used for preparation of linear polymer and for chain termination, respectively, are
  1. A
    CH3SiCl3CH_3SiCl_3CH3​SiCl3​ and Si(CH3)4Si(CH_3)_4Si(CH3​)4​.
  2. B
    (CH3)2SiCl2(CH_3)_2SiCl_2(CH3​)2​SiCl2​ and (CH3)3SiCl(CH_3)_3SiCl(CH3​)3​SiCl.
  3. C
    (CH3)2SiCl2(CH_3)_2SiCl_2(CH3​)2​SiCl2​ and CH3SiCl3CH_3SiCl_3CH3​SiCl3​.
  4. D
    SiCl4SiCl_4SiCl4​ and (CH3)3SiCl(CH_3)_3SiCl(CH3​)3​SiCl.
View written solutionFree

Correct answer: B

  1. Identify the polymer system under hydrolytic conditions

    Hydrolysis of organochlorosilanes gives silicones.

    For example, R2SiCl2+2H2O→R2Si(OH)2+2HClR_2SiCl_2 + 2H_2O \rightarrow R_2Si(OH)_2 + 2HClR2​SiCl2​+2H2​O→R2​Si(OH)2​+2HCl

    Then condensation occurs: n R2Si(OH)2→[−R2Si−O−]n+nH2On\,R_2Si(OH)_2 \rightarrow [-R_2Si-O-]_n + nH_2OnR2​Si(OH)2​→[−R2​Si−O−]n​+nH2​O

    This gives a linear silicone polymer.

  2. Compound used for preparation of linear polymer

    To get a linear polymer, the monomer must be difunctional, so that it can form two bonds in the chain.

    Among the given compounds:

    • CH3SiCl3CH_3SiCl_3CH3​SiCl3​ is trifunctional ⇒\Rightarrow⇒ gives cross-linked/network polymer.
    • (CH3)2SiCl2(CH_3)_2SiCl_2(CH3​)2​SiCl2​ is difunctional ⇒\Rightarrow⇒ gives linear polymer.
    • SiCl4SiCl_4SiCl4​ is tetrafunctional ⇒\Rightarrow⇒ highly cross-linked structure.

    Therefore, the compound for preparation of a linear polymer is: (CH3)2SiCl2(CH_3)_2SiCl_2(CH3​)2​SiCl2​

  3. Compound used for chain termination

    A chain terminator should be monofunctional, so it can cap the growing chain ends without further propagation.

    Among the options:

    • (CH3)3SiCl(CH_3)_3SiCl(CH3​)3​SiCl is monofunctional.

    On hydrolysis: (CH3)3SiCl+H2O→(CH3)3SiOH+HCl(CH_3)_3SiCl + H_2O \rightarrow (CH_3)_3SiOH + HCl(CH3​)3​SiCl+H2​O→(CH3​)3​SiOH+HCl

    This caps the polymer end as a terminal group like −(Si(CH3)3)-(Si(CH_3)_3)−(Si(CH3​)3​) and stops further chain growth.

    Hence, the chain-terminating compound is: (CH3)3SiCl(CH_3)_3SiCl(CH3​)3​SiCl

  4. Check each option

    • A: CH3SiCl3CH_3SiCl_3CH3​SiCl3​ and Si(CH3)4Si(CH_3)_4Si(CH3​)4​

      • First compound gives cross-linked polymer, not linear.
      • Si(CH3)4Si(CH_3)_4Si(CH3​)4​ is not the usual hydrolysable chain terminator.
      • Incorrect.
    • B: (CH3)2SiCl2(CH_3)_2SiCl_2(CH3​)2​SiCl2​ and (CH3)3SiCl(CH_3)_3SiCl(CH3​)3​SiCl

      • First gives linear silicone polymer.
      • Second acts as chain terminator.
      • Correct.
    • C: (CH3)2SiCl2(CH_3)_2SiCl_2(CH3​)2​SiCl2​ and CH3SiCl3CH_3SiCl_3CH3​SiCl3​

      • Second is trifunctional, causes branching/cross-linking, not termination.
      • Incorrect.
    • D: SiCl4SiCl_4SiCl4​ and (CH3)3SiCl(CH_3)_3SiCl(CH3​)3​SiCl

      • SiCl4SiCl_4SiCl4​ gives network polymer, not linear.
      • Incorrect.
  5. Final answer

    The correct pair is: (CH3)2SiCl2 and (CH3)3SiCl\boxed{(CH_3)_2SiCl_2 \text{ and } (CH_3)_3SiCl}(CH3​)2​SiCl2​ and (CH3​)3​SiCl​

    So, Option B is correct.

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