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Polymers question

2019 · Shift 2 · Q6
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Polymers question

2019 · Shift 2 · Q6

JEE AdvancedChemistryPolymersMultiple correct+4 / −1
Choose the correct option(s) from the following.
  1. A
    Teflon is prepared by heating tetrafluoroethene in presence of a persulphate catalyst at high pressure.
  2. B
    Natural rubber is polyisoprene containing trans alkene units
  3. C
    Cellulose has only α\alphaα-D-glucose units that are joined by glycosidic linkages
  4. D
    Nylon-6 has amide linkages
View written solutionFree

Correct answer: A, D

  1. Option A: Teflon

    Teflon is polytetrafluoroethene (PTFE), formed by polymerization of tetrafluoroethene: nextCF2=CF2→(−CF2−CF2−)nn ext{CF}_2=\text{CF}_2 \rightarrow (-\text{CF}_2-\text{CF}_2-)_nnextCF2​=CF2​→(−CF2​−CF2​−)n​

    It is prepared by heating tetrafluoroethene under high pressure in the presence of a free-radical initiator such as persulphate catalyst.

    Hence, A is correct.

  2. Option B: Natural rubber

    Natural rubber is cis-1,4-polyisoprene, not trans.

    • Natural rubber: cis-polyisoprene
    • Gutta-percha: trans-polyisoprene

    Therefore, the statement that natural rubber contains trans alkene units is false.

    Hence, B is incorrect.

  3. Option C: Cellulose

    Cellulose is made up of β\betaβ-D-glucose units, not α\alphaα-D-glucose units. These are joined by β(1→4)\beta(1\rightarrow 4)β(1→4) glycosidic linkages.

    So the statement is wrong because of the word "α\alphaα".

    Hence, C is incorrect.

  4. Option D: Nylon-6

    Nylon-6 is formed from caprolactam and contains repeating amide groups: −NH−(CH2)5−CO−-\mathrm{NH}-(\mathrm{CH}_2)_5-\mathrm{CO}-−NH−(CH2​)5​−CO−

    Therefore, nylon-6 is a polyamide and has amide linkages.

    Hence, D is correct.

Final Answer

The correct options are: A,D\boxed{A, D}A,D​

Comparison with stored answer

Stored correct answer: A, D

My derived answer matches the stored answer.

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