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Chemical Kinetics and Nuclear Chemistry question

2016 · Shift 1 · Q2
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Chemical Kinetics and Nuclear Chemistry question

2016 · Shift 1 · Q2

JEE AdvancedChemistryChemical Kinetics and Nuclear ChemistryMultiple correct+4 / −2
According to the Arrhenius equation,
  1. A
    a high activation energy usually implies a fast reaction
  2. B
    rate constant increases with increase in temperature. This is due to a greater number of collisions whose energy exceeds the activation energy
  3. C
    higher the magnitude of activation energy, stronger is the temperature dependence of the rate constant.
  4. D
    the pre-exponential factor is a measure of the rate at which collisions occur, irrespective of their energy.
View written solutionFree

Correct answer: B, C, D

The Arrhenius equation describes the temperature dependence of the rate constant, kkk, for a chemical reaction:

k=Ae−Ea/RTk = A e^{-E_a / RT}k=Ae−Ea​/RT

where:

  • kkk is the rate constant
  • AAA is the pre-exponential factor (or frequency factor)
  • EaE_aEa​ is the activation energy
  • RRR is the universal gas constant
  • TTT is the absolute temperature in Kelvin

Let's evaluate each option based on this equation.

Step 1: Analyze Option A

A: a high activation energy usually implies a fast reaction

The rate of a reaction is directly proportional to the rate constant, kkk. According to the Arrhenius equation, the rate constant kkk is related to the activation energy EaE_aEa​ by the term e−Ea/RTe^{-E_a / RT}e−Ea​/RT.

  • If EaE_aEa​ is high, the exponent −Ea/RT-E_a / RT−Ea​/RT will be a large negative number.
  • The exponential of a large negative number, e−Ea/RTe^{-E_a / RT}e−Ea​/RT, will be a very small positive number.
  • This makes the rate constant kkk small (k=Aimessmall numberk = A imes \text{small number}k=Aimessmall number).
  • A small rate constant implies a slow reaction.

Therefore, a high activation energy implies a slow reaction, not a fast one. Option A is incorrect.

Step 2: Analyze Option B

B: rate constant increases with increase in temperature. This is due to a greater number of collisions whose energy exceeds the activation energy

Let's examine the effect of temperature (TTT) on kkk.

  • As temperature TTT increases, the denominator RTRTRT increases.
  • The term Ea/RTE_a / RTEa​/RT decreases.
  • The exponent −Ea/RT-E_a / RT−Ea​/RT becomes less negative (i.e., it increases).
  • Since the exponential function exe^xex is an increasing function, the term e−Ea/RTe^{-E_a / RT}e−Ea​/RT increases as TTT increases.
  • Consequently, the rate constant kkk increases with an increase in temperature.

The physical reason for this is that at higher temperatures, the average kinetic energy of the reacting molecules increases. This results in a larger fraction of molecules possessing energy equal to or greater than the activation energy. The term e−Ea/RTe^{-E_a / RT}e−Ea​/RT represents this fraction. A larger fraction of molecules with sufficient energy leads to more effective collisions and a higher reaction rate. Thus, the statement is correct. Option B is correct.

Step 3: Analyze Option C

C: higher the magnitude of activation energy, stronger is the temperature dependence of the rate constant.

To see the temperature dependence, we can differentiate the natural logarithm of the Arrhenius equation with respect to temperature:

ln⁡k=ln⁡A−EaRT\ln k = \ln A - \frac{E_a}{RT}lnk=lnA−RTEa​​

d(ln⁡k)dT=ddT(ln⁡A−EaRT−1)\frac{d(\ln k)}{dT} = \frac{d}{dT} \left( \ln A - \frac{E_a}{R}T^{-1} \right)dTd(lnk)​=dTd​(lnA−REa​​T−1)

d(ln⁡k)dT=0−EaR(−1)T−2=EaRT2\frac{d(\ln k)}{dT} = 0 - \frac{E_a}{R}(-1)T^{-2} = \frac{E_a}{RT^2}dTd(lnk)​=0−REa​​(−1)T−2=RT2Ea​​

The term d(ln⁡k)dT\frac{d(\ln k)}{dT}dTd(lnk)​ represents the sensitivity of the rate constant to changes in temperature. The equation shows that this sensitivity is directly proportional to the activation energy, EaE_aEa​. A larger EaE_aEa​ leads to a larger value of d(ln⁡k)dT\frac{d(\ln k)}{dT}dTd(lnk)​, meaning the rate constant changes more significantly with a given change in temperature. Therefore, a higher activation energy implies a stronger temperature dependence of the rate constant. Option C is correct.

Step 4: Analyze Option D

D: the pre-exponential factor is a measure of the rate at which collisions occur, irrespective of their energy.

The pre-exponential factor, AAA, is also known as the frequency factor. It is related to the frequency of collisions between reactant molecules.

  • In the context of the Arrhenius equation, AAA represents the rate constant when the temperature is infinitely high (T→∞T \to \inftyT→∞). At infinite temperature, the exponential term e−Ea/RTe^{-E_a / RT}e−Ea​/RT approaches 1, so k→Ak \to Ak→A.
  • This means AAA is the maximum possible rate constant, which would be achieved if the energy barrier (EaE_aEa​) was not a limiting factor.
  • According to collision theory, A=pZA = pZA=pZ, where ZZZ is the collision frequency and ppp is the steric (orientation) factor.
  • Thus, AAA is a measure of the frequency of collisions (with the correct orientation). The energy requirement for the reaction is accounted for by the exponential term, e−Ea/RTe^{-E_a / RT}e−Ea​/RT. So, AAA can be seen as representing the rate of collisions, irrespective of their energy. Option D is correct.

Conclusion

Based on the analysis:

  • Option A is incorrect.
  • Option B is correct.
  • Option C is correct.
  • Option D is correct.

The correct options are B, C, and D.

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