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Chemical Kinetics and Nuclear Chemistry question

2009 · Shift 2 · Q1
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Chemical Kinetics and Nuclear Chemistry question

2009 · Shift 2 · Q1

JEE AdvancedChemistryChemical Kinetics and Nuclear ChemistryMCQ+3 / −1
For a first-order reaction A →\to→ P, the temperature (T) dependent rate constant (k) was found to follow the equation log⁡k=−(2000)1T+6.0\log k = - (2000){1 \over T} + 6.0logk=−(2000)T1​+6.0. The pre-exponential factor A and activation energy EaE_aEa​, respectively, are
  1. A
    1.0×106 s−11.0\times10^6~\mathrm{s^{-1}}1.0×106 s−1 and 9.2 kJ mol −1{}^{-1}−1
  2. B
    6.0 s−16.0~\mathrm{s^{-1}}6.0 s−1 and 16.6 kJ mol −1{}^{-1}−1
  3. C
    1.0×106 s−11.0\times10^6~\mathrm{s^{-1}}1.0×106 s−1 and 16.6 kJ mol −1{}^{-1}−1
  4. D
    1.0×106 s−11.0\times10^6~\mathrm{s^{-1}}1.0×106 s−1 and 38.3 kJ mol −1{}^{-1}−1
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