Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Moving Charges and Magnetism question

2010 · Q87
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /NEET
  3. /Physics
  4. /Moving Charges and Magnetism
  5. /2010 · Q87

Moving Charges and Magnetism question

2010 · Q87

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A particle having a mass of 10−-−2 kg carries a charge of 5 ×\times× 10−-−8 C. The particle is given an initial horizontal velocity of 105 m s−-−1 in the presence of electric field E→\overrightarrow EE and magnetic field B→\overrightarrow BB. To keep the particle moving in a horizontal direction, it is necessary that
(1)  B→\overrightarrow BB should be perpendicular to the direction of velocity and E→\overrightarrow EE should be along the direction of velocity

(2)  Both B→\overrightarrow BB and E→\overrightarrow EE should be along the direction of velocity

(3)  Both B→\overrightarrow BB and E→\overrightarrow EE are mutually perpendicular and perpendicular to the direction of velocity.

(4)  B→\overrightarrow BB should be along the direction of velocity and E→\overrightarrow EE should be perpendicular to the direction of velocity

Which one of the following pairs of statements is possible ?
  1. A
    (1) and (3)
  2. B
    (3) and (4)
  3. C
    (2) and (3)
  4. D
    (2) and (4)
View written solutionFree

Correct answer: C

Force due to electric field acts along the direction of the electric field but force due to the magnetic field acts along a direction perpendicular to both the velocity of the charged particle and the magnetic field. Hence both statements (2) and (3) are true. In statement (2), magnetic force is zero, so, electric force will keep the particle continue to move in horizontal direction. In statement (3), both electric and magnetic forces will be opposite to each other. If their magnitudes will be equal then the particle will continue horizontal motion.

PreviousNext

More from Moving Charges and Magnetism

  • Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the center of the ring is2010 · MCQ
  • A galvanometer has a coil of resistance 100 ohm and gives a full scale deflection for 30 mA current. If it is to work as a voltmeter of 30 volt range, the resistance required to be added will be2010 · MCQ
  • A galvanometer has a coil of resistance 100 ohm and gives a full scale deflection for 30 mA current. If it is to work as a voltmeter of 30 volt range, the resistance required to be added will be2010 · MCQ
  • A square current carrying loop is suspended in a uniform magnetic field acting in the plane of the loop. If the force on one arm of the loop is the net force on the remaining three arms of the loop is2010 · MCQ
  • A galvanometer havings a coil resistance of 60 Ω shows full scale deflection when a current of 1.0 amp passes through it. It can be converted into an ammeter to read currents upto 5.0 amp by2009 · MCQ
  • The magnetic force acting on a charged particle of charge −2 μC in a magnetic frield of 2 T acting in y direction, when the particle velocity is (2i+3j​)×106ms−12009 · MCQ
  • Under the influence of a uniform magnetic field, a charged particle moves with constant speed v in a circle of radius R. The time period of rotation of the particle2009 · MCQ
  • A particle of mass m, charge Q and kinetic energy T enters a transverse uniform magnetic field of induction B. After 3 seconds the kinetic energy of the particle will be2008 · MCQ