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Moving Charges and Magnetism question

2009 · Q135
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Moving Charges and Magnetism question

2009 · Q135

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A galvanometer havings a coil resistance of 60 Ω\OmegaΩ shows full scale deflection when a current of 1.0 amp passes through it. It can be converted into an ammeter to read currents upto 5.0 amp by
  1. A
    putting in series a resistance of 15 Ω\OmegaΩ
  2. B
    putting in series a resistance of 240 Ω\OmegaΩ
  3. C
    putting in parallel a resistance of 15 Ω\OmegaΩ
  4. D
    putting in parallel a resistance of 240 Ω\OmegaΩ
View written solutionFree

Correct answer: C

G = 60 Ω\Omega Ω , Ig = 1.0A, I = 5A.

Let S be the shunt resistance connected in parallel to galvanometer

Ig G = (I – Ig) S,

S=IgGI−Ig=15−1×60=1.0×604=15ΩS = {{{I_g}G} \over {I - {I_g}}} = {1 \over {5 - 1}} \times 60 = {{1.0 \times 60} \over 4} = 15\Omega S=I−Ig​Ig​G​=5−11​×60=41.0×60​=15Ω

Thus by putting 15 Ω\Omega Ω in parallel, the galvanometer can be converted into an ammeter.

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