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Moving Charges and Magnetism question

2010 · Q86
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Moving Charges and Magnetism question

2010 · Q86

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A closely wound solenoid of 2000 turns and area of cross-section 1.5 ×\times× 10−-−4 m2 carries a current of 2.0 A. It is suspended through its centre and perpendicular to its length, allowing it to turn in a horizontal plane in a uniform magnetic field 5 ×\times× 10−-−2 tesla making an angle of 30o with the axis of the solenoid. The torque on the solenoid will be
  1. A
    3 ×\times× 10−-−3 N m
  2. B
    1.5 ×\times× 10−-−3 N m
  3. C
    1.5 ×\times× 10−-−2 N m
  4. D
    3 ×\times× 10−-−2 N m
View written solutionFree

Correct answer: C

Magnetic moment of the loop.

M = NIA = 2000 × 2 × 1.5 × 10–4 = 0.6 J/T

Torque τ\tau τ = MBsin30°

=0.6×5×10−2×12=1.5×10−2 Nm = 0.6 \times 5 \times {10^{ - 2}} \times {1 \over 2} = 1.5 \times {10^{ - 2}}\,Nm=0.6×5×10−2×21​=1.5×10−2Nm

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