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Moving Charges and Magnetism question

2009 · Q136
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Moving Charges and Magnetism question

2009 · Q136

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
The magnetic force acting on a charged particle of charge −-−2 μ\muμC in a magnetic frield of 2 T acting in y direction, when the particle velocity is (2i^+3j^)×106 ms−1\left( {2\widehat i + 3\widehat j} \right) \times {10^6}\,m{s^{ - 1}}(2i+3j​)×106ms−1
  1. A
    4 N in z direction
  2. B
    8 N in y direction
  3. C
    8 N in z direction
  4. D
    8 N in −-− z direction
View written solutionFree

Correct answer: D

The magnetic force acting on the charged paraticle is given by

F→=q(v→×B→)\overrightarrow F = q\left( {\overrightarrow v \times \overrightarrow B } \right)F=q(v×B)

=(−2×10−6)[{(2i^+3j^)×106}×(2j^)] = \left( { - 2 \times {{10}^{ - 6}}} \right)\left[ {\left\{ {\left( {2\widehat i + 3\widehat j} \right) \times {{10}^6}} \right\} \times \left( {2\widehat j} \right)} \right]=(−2×10−6)[{(2i+3j​)×106}×(2j​)]

=−4(2k^) = - 4\left( {2\widehat k} \right)=−4(2k)

=−8k^ = - 8\widehat k=−8k

∴\therefore∴ Force is of 8N along – z-axis.

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