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Moving Charges and Magnetism question

2004 · Q125
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Moving Charges and Magnetism question

2004 · Q125

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A galvanometer of 50 ohm resistance has 25 divisions. A current of 4 ×\times× 10−-−4 ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of
  1. A
    2500 Ω2500\,\Omega2500Ω as a shunt
  2. B
    2450 Ω\OmegaΩ as a shunt
  3. C
    2550 Ω\OmegaΩ in series
  4. D
    2450 Ω\OmegaΩ in series
View written solutionFree

Correct answer: D

The total current shown by the galvanometer,

Ig = 25 ×\times× 4 ×\times× 10-4 A = 10-2 A

The value of resistance connected in series to convert galvanometer into voltmeter of 25 V is

V = Ig(Re + Rg)

⇒\Rightarrow⇒ Re = VIg−Rg{V \over {{I_g}}} - {R_g}Ig​V​−Rg​ = 2450 Ω\Omega Ω

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