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Moving Charges and Magnetism question

2001 · Q129
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Moving Charges and Magnetism question

2001 · Q129

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
An electron having mass m and kinetic energy E anter in uniform magnetic field B perpendiculaly, then its frequency will be
  1. A
    eEqvB{{eE} \over {qvB}}qvBeE​
  2. B
    2πmeB{{2\pi m} \over {eB}}eB2πm​
  3. C
    eB2πm{{eB} \over {2\pi m}}2πmeB​
  4. D
    2meBE{{2m} \over {eBE}}eBE2m​
View written solutionFree

Correct answer: C

The frequency of revolution of charged particle in a perpendicular magnetic field is

f=1T=12πrv=v2πrf = {1 \over T} = {1 \over {{{2\pi r} \over v}}} = {v \over {2\pi r}} f=T1​=v2πr​1​=2πrv​

=v2π×eBmv=eB2πm= {v \over {2\pi }} \times {{eB} \over {mv}} = {{eB} \over {2\pi m}}=2πv​×mveB​=2πmeB​

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