NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A long solenoid carrying a current producess a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is
- AB/2
- BB
- C2B
- D4B
View written solutionFree
Correct answer: B
Magnetic field induction at point inside the solenoid of length l, having n turns per unit length carrying current i is given by
B = 0ni
If i doubled, n halved then B remains same.
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