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Moving Charges and Magnetism question

2005 · Q132
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Moving Charges and Magnetism question

2005 · Q132

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
A very long straight wire carries a current III. At the instant when a charge +Q at point P has velocity v→\overrightarrow vv, as shown, the force on the charge is

AIPMT 2005 Physics - Moving Charges and Magnetism Question 36 English
  1. A
    along Oy
  2. B
    opposite to Oy
  3. C
    along Ox
  4. D
    opposite to Ox
View written solutionFree

Correct answer: A

The direction of B→\overrightarrow B B is due to i is acting inwards i.e. into the paper along (−k^)\left( { - \widehat k} \right)(−k).

∴\therefore∴ The magnetic force

F→=Q(v→×B→)=Q(v→i^)×B(−k^)=QvBj^\overrightarrow F = Q\left( {\overrightarrow v \times \overrightarrow B } \right) = Q\left( {\overrightarrow v \widehat i} \right) \times B\left( { - \widehat k} \right) = QvB\widehat jF=Q(v×B)=Q(vi)×B(−k)=QvBj​

So, F→\overrightarrow F F is along Oy direction.

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