NEETPhysicsCurrent ElectricityMCQ+4 / −1
10 resistors, each of resistance are connected in series to a battery of emf and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased times. The value of is :
- A100
- B1
- C1000
- D10
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Correct answer: A
$$\mathrm{I}_{\mathrm{S}}=\frac{E}{10 R}$$ ..... (1)
$$\mathrm{I}_{\mathrm{P}}=\frac{\mathrm{E}}{\mathrm{R} / 10}=\frac{10 \mathrm{E}}{\mathrm{R}}$$ .... (2)
$$\mathrm{n}=\frac{\mathrm{I}_{\mathrm{P}}}{\mathrm{I}_{\mathrm{S}}}=100 \Rightarrow \mathrm{n}=100$$
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