NEETPhysicsCurrent ElectricityMCQ+4 / −1
The equivalent resistance of the infinite network given below is :

- A
- B
- C
- D
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Correct answer: D
Let net resistance of the given infinite network be 'R'
Now, the circuit can be modified as

Now, $${R_{net}} = R = 1 + 1 + {R \over {R + 1}}$$
$\therefore$ $$R = 2 + {R \over {R + 1}}$$
$${R^2} + R = 2R + 2 + R$$
${R^2} - 2R - 2 = 0$
$$R = \left( {{{2\, \pm \,\sqrt {4 + 8} } \over 2}} \right)$$
$$R = \left( {1 + \sqrt 3 } \right)\Omega $$
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