NEETPhysicsCurrent ElectricityMCQ+4 / −1
A cell of emf 4 V and internal resistance 0.5 is connected to a 7.5 external resistance. The terminal potential difference of the cell is
- A0.375 V
- B3.75 V
- C4.25 V
- D4 V
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Correct answer: B

From Kirchhoff's loop law :
$V - Ir - IR = 0$
$$ \Rightarrow I = \left( {{V \over {r + R}}} \right)$$
Terminal potential difference across cell,
${V_{AB}} = IR$
$${V_{AB}} = {{RV} \over {r + R}}$$
$$ = {{7.5 \times 4} \over {0.5 + 7.5}} = 3.75\,V$$
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