NEETPhysicsCurrent ElectricityMCQ+4 / −1
Two resistors of resistance, 100 and 200 are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in 100 to that in 200 in a given time is
- A1 : 2
- B2 : 1
- C1 : 4
- D4 : 1
View written solutionFree
Correct answer: B
For parallel combination
$$P = {{{V^2}} \over R}$$
$${{{P_1}} \over {{P_2}}} = {{{R_2}} \over {{R_1}}}$$
$$ \Rightarrow {{{P_1}} \over {{P_2}}} = {{200} \over {100}} = {2 \over 1}$$
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