NEETPhysicsCurrent ElectricityMCQ+4 / −1
A copper wire of length 10 m and radius m has electrical resistance of 10 . The current density in the wire for an electric field strength of 10 (V/m) is
- A104 A/m2
- B106 A/m2
- C105 A/m2
- D105 A/m2
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Correct answer: D
Resistance, $$R = \rho {L \over A} = {L \over {\sigma A}}$$
$$ \Rightarrow \sigma = {L \over {RA}}$$
Also current density $$j = \sigma E = {{LE} \over {RA}}$$
$$J = {{10 \times 10} \over {10 \times \pi {{\left( {{{{{10}^{ - 2}}} \over {\sqrt \pi }}} \right)}^2}}} = {{100} \over {10 \times \pi \times \left( {{{{{10}^{ - 4}}} \over \pi }} \right)}}$$
$ = {10^5}$ A/m2
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