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Current Electricity question

2009 · Q134
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Current Electricity question

2009 · Q134

NEETPhysicsCurrent ElectricityMCQ+4 / −1
A student measures the terminal potential difference (V) of a cell (of emf ε\varepsilonε and internal resistance r) as a function of the current (I) flowing through it. The slope, and intercept, of the graph between V and I, then respectively, equal
  1. A
    −-− r and ε\varepsilonε
  2. B
    r and −-− ε\varepsilonε
  3. C
    −-− ε\varepsilonε and r
  4. D
    ε\varepsilonε and −-− r
View written solutionFree

Correct answer: A

The terminal potential difference of a cell is given by V + Ir = ε\varepsilon ε

V = VA – VB

⇒\Rightarrow⇒ V = ε\varepsilon ε – Ir

⇒dVdI=−r \Rightarrow {{dV} \over {dI}} = - r⇒dIdV​=−r, Also for, i = 0 then V = ε\varepsilon ε

∴\therefore∴ slope = – r, intercept = ε\varepsilon ε

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