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Current Electricity question

2008 · Q136
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Current Electricity question

2008 · Q136

NEETPhysicsCurrent ElectricityMCQ+4 / −1
A wire of a certain material is stretched slowly by ten percent. Its new resistance and specific resistance become respectively
  1. A
    both remain the same
  2. B
    1.1 times, 1.1 times
  3. C
    1.2 times, 1.1 times
  4. D
    1.21 times, same
View written solutionFree

Correct answer: D

Δll=0.1{{\Delta l} \over l} = 0.1lΔl​=0.1  ∴\therefore∴ l=1.1l = 1.1l=1.1

but the area also decreases by 0.1.

mass = ρlA=Vρ\rho lA = V\rho ρlA=Vρ, ln⁡l+ln⁡A=ln⁡\ln l + \ln A = \ln lnl+lnA=ln mass.

∴\therefore∴ Δll+ΔAA=0⇒Δll=−ΔAA{{\Delta l} \over l} + {{\Delta A} \over A} = 0 \Rightarrow {{\Delta l} \over l} = {{ - \Delta A} \over A}lΔl​+AΔA​=0⇒lΔl​=A−ΔA​

Length increases by 0.1, resistance increases, area decreases by 0.1, then also resistance will increase. Total increase in resistance is approximately 1.2 times, due to increase in length and decrease in area. But specific resistance does not change.

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