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Current Electricity question

2007 · Q110
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Current Electricity question

2007 · Q110

NEETPhysicsCurrent ElectricityMCQ+4 / −1
The total power dissipated in watt in the circuit shown here is

AIPMT 2007 Physics - Current Electricity Question 69 English
  1. A
    40
  2. B
    54
  3. C
    4
  4. D
    16
View written solutionFree

Correct answer: B

Power dissipiated = P

=V2R=(18)26=54W = {{{V^2}} \over R} = {{{{\left( {18} \right)}^2}} \over 6} = 54W=RV2​=6(18)2​=54W

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