NEETPhysicsAlternating CurrentMCQ+4 / −1
A standard filament lamp consumes 100 W when connected to 200 V ac mains supply. The peak current through the bulb will be :
- A2 A
- B0.707 A
- C1 A
- D1.414 A
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Correct answer: B
$${P_{avg}} = {V_{rms}} \times {I_{rms}} \times \cos \phi $$
Here, $\phi = 0^\circ $ as current and voltage are in same phase in a resistor.
$$ \Rightarrow 100 = 200 \times {I_{rms}} \Rightarrow {I_{rms}} = {1 \over 2} \Rightarrow {{{I_0}} \over {\sqrt 2 }} = {1 \over 2} \Rightarrow {I_0} = {1 \over {\sqrt 2 }} = 0.707\,A$$
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