NEETPhysicsAlternating CurrentMCQ+4 / −1
An inductor of inductance 2 mH is connected to a 220 V, 50 Hz ac source. Let the inductive reactance in the circuit is X1. If a 220 V dc source replace the ac source in the circuit, then the inductive reactance in the circuit is X2. X1 and X2 respectively are :
- A0.628 , infinity
- B6.28 , zero
- C6.28 , infinity
- D0.628 , zero
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Correct answer: D
We know, for A.C. source
${X_L} = \omega L$
$ = 2\pi f(L)$
$$ = 100\pi (2 \times {10^{ - 3}})$$
$$ = 0.2\pi \,\Omega = 0.628\,\Omega $$
For D.C. source
The inductor behaves as a closed circuit offering no resistance at all (at steady state) as $\omega = 0$ (For D.C.)
$\therefore$ ${X_L} = 0\,\Omega $
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