NEETChemistrySolutionsMCQ+4 / −1
0.5 molal aqueous solution of a weak acid (HX) is 20% ionised. If Kf for water is 1.86 K kg mol1, the lowering in freezing point of the solution is
- A0.56 K
- B1.12 K
- C0.56 K
- D1.12 K
View written solutionFree
Correct answer: B
Total moles = 1 – $\alpha $ + $\alpha $ + $\alpha $ = 1 + $\alpha $
$ \therefore $ i = $${{1 + \alpha } \over 1}$$
Given, $\alpha $ = 20% = 0.2
$ \therefore $ i = 1 + $\alpha $ = 1 + 0.2 = 1.2
$\Delta $Tf = ikf m = 1.2 × 1.86 × 0.5 = 1.12 K
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