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Solutions question

2005 · Q89
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Solutions question

2005 · Q89

NEETChemistrySolutionsMCQ+4 / −1
The vapour pressure of two liquids P and Q are 80 and 60 torr, respectively. The total vapour pressure of solution obtained by mixing 3 mole of P and 2 mole of Q would be
  1. A
    72 torr
  2. B
    140 torr
  3. C
    68 torr
  4. D
    20 torr
View written solutionFree

Correct answer: A

Hence total vapour pressure

= [(Mole fraction of P) × (Vapour pressure of P)]

  • [(Mole fraction of Q) × Vapour pressure of Q)]

    = (35×80+25×60)\left( {{3 \over 5} \times 80 + {2 \over 5} \times 60} \right)(53​×80+52​×60)

    = 48 + 24 = 72 torr
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